x^(2/3)-3x^(1/3)-18=0

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Solution for x^(2/3)-3x^(1/3)-18=0 equation: 


x in (-oo:+oo)

x^(2/3)-(3*x^(1/3))-18 = 0

x^(2/3)-3*x^(1/3)-18 = 0

t_1 = x^(1/3)

1*t_1^2-3*t_1^1-18 = 0

t_1^2-3*t_1-18 = 0

DELTA = (-3)^2-(-18*1*4)

DELTA = 81

DELTA > 0

t_1 = (81^(1/2)+3)/(1*2) or t_1 = (3-81^(1/2))/(1*2)

t_1 = 6 or t_1 = -3

t_1 = -3

x^(1/3)+3 = 0

1*x^(1/3) = -3 // : 1

x^(1/3) = -3

( -3 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 6

x^(1/3)-6 = 0

1*x^(1/3) = 6 // : 1

x^(1/3) = 6

x^(1/3) = 6 // ^ 3

x = 216

x = 216

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